3x²y + 2xy = sin(y²) help pls

differentiate^

3x²y + 2xy = sin(y²)

I will assume we are finding dy/dx

3x^2 (dy/dx) + 6xy + 2x dy/dx + 2y = cos(y^2) (2y) dy/dx

bring all terms containing dy/dx to left side, factor out the dy/dx
and isolated dy/dx using simple algebra

To solve the equation 3x²y + 2xy = sin(y²), we need to isolate either x or y and solve for it.

Let's solve for y. Start by rearranging the equation:

3x²y + 2xy = sin(y²)

Factor out y from the terms on the left side:

y(3x² + 2x) = sin(y²)

Now divide both sides of the equation by (3x² + 2x):

y = sin(y²) / (3x² + 2x)

This gives us the solution for y in terms of x. However, solving for x may not be possible at this point since y is still present in the equation. If you have additional information or constraints, such as the value of y, you can substitute it into the equation to find the corresponding value of x.