A stone propelled from a catapult with a speed of the 50m/s^1 attains a height of 100m.calculate the angle of projection (c) the range attained
I guess g = 9.81 m/s^2 ?
s = 50 m/s
Vi = s sin A = 50 sin A
v = Vi - g t
at top v = 0
so
0 = Vi - 9.81 t
t = Vi / 9.81 at top
h = 0 + Vi t - (9.81/2) t^2 = 100
(9.81/2) t^2 - Vi t + 100 = 0
(9.81/2) (Vi/9.81)^2 - Vi (Vi/9.81) + 100 = 0
Vi^2/(2*9.81) - Vi^2/9.81 +100 = 0
Vi^2 /(2*9.81) = 100
Vi^2 = 1962
Vi = 44.3 m/s = 50 sin A
sin A = .886
A = 62.4 degrees above horizontal
now get t
time in air = 2 t
range = 50 cos A * 2 t