a car accelerate uniformly from 20m/s to 50m/s in 6sec .what is the distance traveled by the car during the 4th second?
a = (50-20)/6
v(t) = 20 + at
So, find v(3) and v(4)
Starting at t=0
s(t) = v(t)*t + 1/2 at^2
you want s(4)-s(3)
v(t) = 20 + at
So, find v(3) and v(4)
Starting at t=0
s(t) = v(t)*t + 1/2 at^2
you want s(4)-s(3)