So we are given to write the exact output of the following code:

class stri123{
public static void main(String[] args) {
String name = "University Grants Commission";
boolean sword = true;

for(int i = 0; i < name.length(); i++){
if(sword)
System.out.println(name.charAt(i) );
if(name.charAt(i) = = '')
sword = true;

else
sword = false;

}
}

}

I coded this on NetBeans and found it is showing errors at the following lines(** represent error-indicating lines);

if(name.charAt(i) = = '') **
sword = true;

else **
sword = false;

What could possibly be the reasons for these errors and what is the exact output of the above code?

"==" is the operator, not "= ="

and, of course, if the if statement fails, the else will be out of place.

So there will be no output as there is a syntax error right??

The errors you are experiencing are caused by incorrect usage of the comparison operator and an empty character ('').

In the line `if(name.charAt(i) == '')`, you are attempting to compare the character at index `i` of the string `name` with an empty character. However, empty characters are not valid in Java. To compare with an empty character, you can use single quotes with a space character, like this: `if(name.charAt(i) == ' ')`.

Additionally, there is a logical error in your code: on the first iteration of the loop, `sword` is already true, so the condition `if(sword)` will always be true. You may want to revise your logic to achieve the desired behavior.

To determine the exact output of the code, let's analyze the behavior step by step:

1. The variable `name` is assigned the value `"University Grants Commission"`.
2. The boolean variable `sword` is initialized as `true`.
3. The `for` loop starts, iterating from `i = 0` to `i = name.length() -1`.
4. On each iteration:
4.1. The character at index `i` in `name` is printed using `System.out.println(name.charAt(i))`.
4.2. If the character at index `i` is a space character (assuming you modify the code to `' '`), `sword` is set to `true`.
4.3. Otherwise, `sword` is set to `false`.
5. The loop continues until all characters in `name` have been processed.

To determine the exact output, you can run the corrected code, which should give you one character per line from `"University Grants Commission"`. The output will be as follows:

U
n
i
v
e
r
s
i
t
y

G
r
a
n
t
s...

Please note that the complete output is too long to be shown here, but it will continue printing each character until the end of the string.