Math

Find the maximum area of a triangle formed in the first quadrant by the x -axis, y -axis and a tangent line to the graph of f=(x+10)^-2.

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asked by Vera
  1. f'(x) = -2/(x+10)^3
    So, the tangent line through (h,k) on the curve is
    y - 1/(h+10)^2 = -2/(h+10)^3 (x-h)

    Find the intercepts of that line (a,0) and (0,b)
    and the area is A = ab/2
    Now find where dA/dh = 0 for maximum area

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