Solve for x:

2 + 3(x + 2x) = −2x(2 − 4) + 1
a)-5
b)-1/5
c)5
d)1/5
i think it might be a i am very confused

too bad you didn't show your work ...

2 + 3(x + 2x) = −2x(2 − 4) + 1
2 + 3(3x) = -2x(-2) + 1
2 + 9x = 4x + 1
5x = -1
x = -1/5

Next time, show what you did, instead of just guessing and groping for an answer.

Not that a portfolio has anything to do with solving a problem...

thank you i will show work next time

To solve for x in the equation:

2 + 3(x + 2x) = -2x(2 - 4) + 1

We will first simplify both sides of the equation:
Starting with the left side, we will distribute 3 to (x + 2x):
2 + 3(x + 2x) = 2 + 3(3x) = 2 + 9x

On the right side, we will simplify -2x(2 - 4) + 1:
-2x(2 - 4) + 1 = -2x(-2) + 1 = 4x + 1

Our simplified equation becomes:
2 + 9x = 4x + 1

Next, we want to isolate x on one side of the equation. To do that, we will move the 4x term to the left side by subtracting 4x from both sides:
2 + 9x - 4x = 4x - 4x + 1
2 + 5x = 1

Now, we will move the 2 term to the right side by subtracting 2 from both sides:
2 + 5x - 2 = 1 - 2
5x = -1

Finally, we isolate x by dividing both sides by 5:
5x/5 = -1/5
x = -1/5

Therefore, the value of x that satisfies the equation is x = -1/5, which corresponds to option b) -1/5.

I forgot to say this is a portfolio