Hillary and Charlene both drove from City A to City B. At 10a, Hilary left City A and drove at an average speed of 120km/h. Charlene drove at an average speed of 144 km/h and took 50 mins. She arrived at City B at the same time as Hillary. Find the time Charlene left City A.
d1 = d2.
V1*T1 = V2*T2.
120 * T1= 144 * (50/60),
T1 = 1 h. = Hillary's driving time.
10 AM + 1h = 11:00 AM = their arrival time.
11:00 - 55 = 10:60 - 55 = 10:05 AM. = The time Charlene left city A.
"Charlene drove at an average speed of 144 km/h and took 50 mins"
---> the distance she drove is 144(50/60) = 120 km
since Hillary went the same distance at 120 km/h, her time was
120/120 = 1 hour
Can you take it from there?
To find the time Charlene left City A, we need to calculate the time it took her to reach City B.
We know that Charlene drove at an average speed of 144 km/h and arrived at City B at the same time as Hillary, who drove at an average speed of 120 km/h.
Let's first convert Charlene's travel time to hours. We're given that she took 50 minutes, which is (50/60) = 0.83 hours.
Next, let's determine the distance traveled by Charlene. Since time is the same for both Charlene and Hillary, we can use the formula:
Distance = Speed × Time
Let's call the distance traveled by both Hillary and Charlene as 'D'.
For Charlene, we have:
D = 144 km/h × 0.83 hours
D = 119.52 km
Now, we know that Charlene traveled a distance of 119.52 km from City A to City B. To find the time Charlene left City A, we need to calculate the time it took her to cover this distance.
Time = Distance / Speed
Time = 119.52 km / 144 km/h
Time ≈ 0.83 hours
Since Charlene took 0.83 hours to travel from City A to City B, and we know she left at 10:00 am, we can subtract 0.83 hours from 10:00 am to find the time she left City A.
The time Charlene left City A is approximately 9:00 am.