what is the preimage of (3,5) under the translation (x,y) > (x - 4,y + 6)
To find the preimage of the point (3,5) under the translation (x,y) → (x - 4,y + 6), we need to reverse the translation by applying its inverse operation.
The inverse operation of this translation is (x,y) → (x + 4, y - 6).
To calculate the preimage of (3,5), we need to add 4 to the x-coordinate (3 + 4 = 7) and subtract 6 from the y-coordinate (5 - 6 = -1).
Therefore, the preimage of the point (3,5) under the translation (x,y) → (x - 4,y + 6) is (7, -1).
To find the preimage of a point under a translation, we need to reverse the translation by applying the opposite operations. In this case, the given translation is:
(x, y) → (x - 4, y + 6)
To find the preimage of the point (3, 5), we need to reverse this translation.
Step 1: Reverse the x-translation:
x - 4 = 3
Add 4 to both sides:
x = 7
Step 2: Reverse the y-translation:
y + 6 = 5
Subtract 6 from both sides:
y = -1
Therefore, the preimage of the point (3, 5) under the translation (x,y) → (x - 4, y + 6) is (7, -1).
Okay? What about the Y
Just reverse the operation, that is ....
the 3 is the result of 4 having been subtracted from some number
- it must have been 7
use the same argument to find the y of the point, so it will be (7, ?)