divide 9x2-3x+12 by 3x
just divide each term by 3x. That gives
3x - 1 + 4/x
This is not the right answer to my question
So please write the answer I need
That's how I will get my answer 😊
To divide the polynomial 9x^2 - 3x + 12 by 3x, follow these steps:
Step 1: Ensure that the polynomial is written in standard form, with the terms arranged in descending order of exponents. In this case, the polynomial is already in standard form.
Step 2: Divide the first term of the polynomial (9x^2) by the divisor (3x). The result is 3x.
Step 3: Multiply the divisor (3x) by the result from the previous step (3x), and subtract it from the original polynomial:
(9x^2 - 3x + 12) - (3x * 3x) = 9x^2 - 3x + 12 - 9x^2 = -3x + 12.
Step 4: Repeat step 2 and step 3 with the new polynomial (-3x + 12).
Divide the first term (-3x) by the divisor (3x). The result is -1.
Multiply the divisor (3x) by the result from the previous step (-1), and subtract it from the new polynomial:
(-3x + 12) - (3x * -1) = -3x + 12 + 3x = 12.
Step 5: No more terms remain to be divided. The final result of the division is:
Quotient = 3x - 1
Remainder = 12
Therefore, 9x^2 - 3x + 12, divided by 3x, is equal to 3x - 1 with a remainder of 12.
To divide the polynomial 9x^2 - 3x + 12 by 3x, we can use polynomial long division. Here's how you can do it step by step:
Step 1: Write the division problem in the long division format:
_________
3x | 9x^2 - 3x + 12
Step 2: Divide the first term of the numerator (9x^2) by the divisor (3x), which gives us 3x. Write this result above the line:
3x
___________
3x | 9x^2 - 3x + 12
Step 3: Multiply the divisor (3x) by the quotient (3x), which gives 9x^2. Write this below the line, aligned with the first term of the numerator:
3x
___________
3x | 9x^2 - 3x + 12
- 9x^2
Step 4: Subtract the product (9x^2) from the numerator (9x^2 - 3x + 12). Write the result below the line:
3x
___________
3x | 9x^2 - 3x + 12
- 9x^2
___________
- 3x + 12
Step 5: Bring down the next term of the numerator (-3x):
3x
___________
3x | 9x^2 - 3x + 12
- 9x^2
___________
- 3x + 12
- 3x
Step 6: Divide the first term of the updated numerator (-3x) by the divisor (3x), which gives -1. Write this result above the line:
3x - 1
___________
3x | 9x^2 - 3x + 12
- 9x^2
___________
- 3x + 12
- 3x
Step 7: Multiply the divisor (3x) by the updated quotient (-1), which gives -3x. Write this below the line, aligned with the next term of the numerator:
3x - 1
___________
3x | 9x^2 - 3x + 12
- 9x^2
___________
- 3x + 12
- 3x
___________
0
Step 8: Subtract the product (-3x) from the updated numerator (-3x + 12). Write the result below the line:
3x - 1
___________
3x | 9x^2 - 3x + 12
- 9x^2
___________
- 3x + 12
- 3x
___________
0
Step 9: Since there are no more terms to bring down and the remainder is 0, we have completed the division. The quotient is 3x - 1.
Therefore, the division of 9x^2 - 3x + 12 by 3x is equal to 3x - 1.