Given: ∆ABC, m∠A = 35°, Circle k(O, r=3), O∈ AB, AB is a diameter in the circle passing through point O. AC and CB are chords which intersect. Not stated that <ACB is 90 degrees.
Find: Perimeter of ∆ABC

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  1. angle ACB is in fact 90°, since AB is a diameter.
    So the perimeter is
    p = AB + CB + CA
    = 6 + 6sin35° + 6sin55°

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  2. Thank you

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