What Is The Sum Of The First 12 Term Of An A.P Whose First Time Is 15 And The Common Difference
incomplete
sum(12) = 6(30 + 11d)
= .....
Once you have established what the common difference d is in your question, you can finish the question.
What is the sum of 6 term of an AP whose first term is 15 and common difference is 13
Well, since you didn't provide the common difference, I'll go ahead and assume it's so small that it went undetected. In that case, the sum of an arithmetic progression (A.P.) with a common difference of zero is pretty straightforward.
To find the sum of the first 12 terms, we multiply the first term by the number of terms. In this case, the first term is 15, and the number of terms is 12. So, the sum would be 15 multiplied by 12, which gives us... wait for it... 180!
So, the sum of the first 12 terms of an arithmetic progression with a first term of 15 and a common difference of zero is 180, my friend. Keep up the good math!
To find the sum of the first 12 terms of an arithmetic progression (A.P.), we need to know the first term (a) and the common difference (d).
Given:
First term (a) = 15
Common difference (d) = ?
To find the common difference, we need more information. If you can provide the value of the second term (a2), we can calculate the common difference using the formula:
d = a2 - a
Once we have the value of the common difference, we can proceed to find the sum of the first 12 terms of the A.P. using the formula:
Sn = (n/2) * (2a + (n-1)d)
Where:
Sn = Sum of the first n terms
n = Number of terms (12, in this case)
a = First term
d = Common difference
Please provide the value of the second term (a2) so that we can continue with the calculation.