There are 3 finalists. Two medals; gold &silver awarded.
How many different ways can the medals be awarded?
she said theres 3 finalists
1 gold 2 silver
2 silver 1 gold
and 1 gold 1 silver and one person didn't get awarded
right?
yeah
To find the number of different ways the medals can be awarded, we can use the concept of permutations.
We have 3 finalists for 2 medals (gold and silver). The gold medal can be awarded to any of the 3 finalists, and once the gold medal is awarded, the silver medal can be awarded to any of the remaining 2 finalists.
So, we can find the number of different ways by calculating the number of permutations of 3 finalists taken 2 at a time.
The formula to find permutations is: P(n, r) = n! / (n - r)!
where n is the total number of items and r is the number of items taken at a time.
In this case, we have n = 3 (3 finalists) and r = 2 (2 medals).
Using the formula, we get:
P(3, 2) = 3! / (3 - 2)!
= 3! / 1!
= 3 * 2 * 1 / 1
= 6
Therefore, there are 6 different ways the medals can be awarded.