An object falls freely from rest on a planet
where the acceleration due to gravity is
27 m/s
2
.
After 7 s, what will be its speed?
Answer in units of m/s.
v = at
27 meters/ second^2
meters per second squared
v = 27 meters/second^2 * 7 seconds
To find the speed of the object after 7 seconds, we can use the following equation of motion:
v = u + at,
where v is the final velocity, u is the initial velocity (which is 0 m/s since the object falls from rest), a is the acceleration due to gravity (27 m/s^2), and t is the time (7 seconds).
Substituting the given values into the equation:
v = 0 + (27 m/s^2)(7 s).
Calculating the multiplication:
v = 0 + (189 m/s^2).
Therefore, the speed of the object after 7 seconds is 189 m/s.