# Math

Five years ago, a mother was twice as old as her son. in 6 years time, the sum of their age will be 82. find their present ages

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1. Present age of son ---- x
present age of mother --- y

5 years ago:
son --- x-5
mother --- y-5
y-5 = 2(x-5)
y-5 = 2x - 10
2x - y = 5 or y = 2x - 5

6 years from now:
son --- x+6
mother ---- y + 6
x+6 + y+6 = 82
x + y = 70
x + 2x-5 = 70
3x = 75
x = 25 , then y = 2x-5 = 45

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Reiny
2. Good. Very good

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