What is the equation of the line that passes through the points (15, 9) and
(-2, 9)?
It doesn't give me options.
Given that for all values of x , y = 9
The equation of your line:
y = 9
Thank You!
To find the equation of the line that passes through the points (15, 9) and (-2, 9), we can use the point-slope form of a linear equation, which is y - y1 = m(x - x1).
First, let's calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) = (15, 9) and (x2, y2) = (-2, 9).
m = (9 - 9) / (-2 - 15)
m = 0 / -17
m = 0
As the slope is 0, the equation of the line becomes:
y - 9 = 0(x - 15)
Simplifying further:
y - 9 = 0
Finally, rearranging the equation to put it into slope-intercept form (y = mx + b):
y = 0
So, the equation of the line that passes through the points (15, 9) and (-2, 9) is y = 0.
To find the equation of the line that passes through two points, we can use the slope-intercept form of a linear equation, which is given by: y = mx + b, where m is the slope of the line and b is the y-intercept.
To find the slope (m), we can use the formula:
m = (y2 - y1) / (x2 - x1)
Using the given points (15, 9) and (-2, 9), we have:
x1 = 15, y1 = 9
x2 = -2, y2 = 9
Now, let's substitute these values into the slope formula:
m = (9 - 9) / (-2 - 15)
Since both y coordinates are the same, the numerator is zero. Therefore, the slope of the line is zero.
Now that we have the slope (m = 0), we can use one of the given points (15, 9) to find the y-intercept (b). Let's substitute the values into the slope-intercept form:
9 = 0(15) + b
0 times any number is zero, so we have:
9 = b
Therefore, the y-intercept is 9 (b = 9).
Now we have the slope (m = 0) and the y-intercept (b = 9), so we can write the equation of the line as:
y = 0x + 9
Simplifying further, we get the equation:
y = 9
So, the equation of the line that passes through the points (15, 9) and (-2, 9) is y = 9.