A plane cruising at 232 m/s accelerates at 14 m/s2 for 4.7 s.
What is its final velocity? Answer in units of m/s.
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the acceleration increases the velocity of the plane
v = 232 m/s + (14 m/s^2 * 4.7 s)
To find the final velocity, we can use the formula for acceleration:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
u = 232 m/s (initial velocity)
a = 14 m/s^2 (acceleration)
t = 4.7 s (time)
Substitute the given values into the formula:
v = 232 m/s + 14 m/s^2 * 4.7 s
To solve this equation, multiply the acceleration (14 m/s^2) by the time (4.7 s), then add the result to the initial velocity (232 m/s):
v = 232 m/s + 65.8 m/s
Calculating the sum:
v = 297.8 m/s
Therefore, the plane's final velocity is 297.8 m/s.