50 employees in an office wear eyeglasses.
43
have single-vision correction, and
7
wear bifocals. If two employees are selected at random from this group, what is the probability that both of them wear bifocals? What is the probability that both have single-vision correction?
Round your answers to four decimal places.
there are 50C2 ways of selecting 2 people from 50
bifocals ... there are 7C2 ways of selecting 2 people from 7
... probability is ... (7C2) / (50C2)
single-vision ... there are 43C2 ways of selecting 2 people from 43
... probability is ... (43C2) / (50C2)
You guys are Legends thank you
40 employees in an office wear eyeglasses. 23 have single-vision correction, and 17 wear bifocals. If two employees are selected at random from this group, what is the probability that both of them wear bifocals? What is the probability that both have single-vision correction?
To find the probability that both selected employees wear bifocals, we need to calculate the probability of selecting the first employee who wears bifocals, and then the probability of selecting the second employee who also wears bifocals.
First, let's find the probability of selecting the first employee who wears bifocals. There are 7 employees who wear bifocals out of a total of 50 employees who wear eyeglasses. So, the probability of selecting the first employee wearing bifocals is 7/50.
Next, we need to find the probability of selecting the second employee who wears bifocals. After the first selection, there are now 49 employees left, with 6 employees who wear bifocals. So, the probability of selecting the second employee who wears bifocals is 6/49.
To get the probability that both selected employees wear bifocals, we multiply the probabilities of each selection together:
Probability = (7/50) * (6/49) = 0.01773 (rounded to four decimal places).
Therefore, the probability that both selected employees wear bifocals is approximately 0.0177.
Now let's calculate the probability that both selected employees have single-vision correction.
Similarly, the probability of selecting the first employee with single-vision correction is 43/50, since there are 43 employees with single-vision correction out of 50 employees in total.
After the first selection, there are 49 employees left, with 42 employees having single-vision correction. So, the probability of selecting the second employee with single-vision correction is 42/49.
To get the probability that both selected employees have single-vision correction, we multiply the probabilities of each selection together:
Probability = (43/50) * (42/49) = 0.7224 (rounded to four decimal places).
Therefore, the probability that both selected employees have single-vision correction is approximately 0.7224.
I believe that you must multiply the probability of getting bifocals (7/50) by itself to get the prob of picking two. (7/50)(7/50)
Same idea for single vision correction but use (43/50)(43/50)