Given any Cartesian coordinates, (x,y), there are polar coordinates (r, theta) with -pi/2 < theta <= pi/2. Find polar coordinates for the cartesian coordinates (-9, -8) and (-7, 7).
For (-9, -8), I got r = sqrt(x^2+y^2) = sqrt((-9)^2+(-8)^2) = sqrt(145) = 12.04
For (-7, 7), I got r = sqrt((-7)^2+(7)^2) = sqrt(98) = 9.90
I know I already have the correct angles for theta, which is why I didn't include it here. I just wanted to make sure my answers for "r" were right, since my online homework system was telling me they were incorrect.
might be a significant figure problem. You were given integer distances
try 12.04 is 12
and 9.9 is 10
Your calculations for the values of "r" appear to be correct. For the Cartesian coordinates (-9, -8) and (-7, 7), you have correctly computed the radial distance "r" using the formula r = sqrt(x^2 + y^2), which gives r = sqrt((-9)^2 + (-8)^2) = sqrt(145) ≈ 12.04 for (-9, -8), and r = sqrt((-7)^2 + (7)^2) = sqrt(98) ≈ 9.90 for (-7, 7).
It is possible that your online homework system is expecting the values to be rounded to a certain decimal place or expressed in a different form (e.g. in scientific notation). Make sure to check the instructions or guidelines provided by the system to ensure you are entering the answer in the correct format.