Given g(x)=−2x2+1, find the indicated values: g(−4)
assume you mean
g = -2 x^2 + 1
then if x = -4
g = -2 (16) + 1
= -32 + 1
= -31
assume you mean
g = -2 x^2 + 1
then if x = -4
g = -2 (16) + 1
= -32 + 1
= -31
To find the value of g(-4), we need to substitute -4 into the equation g(x) = -2x^2 + 1.
So, we substitute x = -4 into the equation:
g(-4) = -2(-4)^2 + 1
First, we calculate (-4)^2 which is equal to 16:
g(-4) = -2(16) + 1
Next, we multiply -2 by 16:
g(-4) = -32 + 1
Lastly, we subtract 32 from 1:
g(-4) = -31
Therefore, the value of g(-4) is -31.
To find the value of g(-4), you need to substitute -4 into the expression for g(x) and evaluate it.
The given expression is g(x) = -2x^2 + 1.
So, replacing x with -4, we get g(-4) = -2(-4)^2 + 1.
To solve this, we need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, and Addition and Subtraction from left to right).
First, we simplify -4^2 by squaring -4, which gives us 16.
So, g(-4) = -2(16) + 1.
Next, we multiply -2 by 16, which gives us -32.
Therefore, g(-4) = -32 + 1.
Finally, adding -32 and 1, we get g(-4) = -31.
Hence, the value of g(-4) is -31.