An aircraft has a liftoff speed of 33 m/s. What minimum constant acceleration does this require if the aircraft is to be airborne after a takeoff run of 240m?

34 To find the minimum constant acceleration required, we can use the equations of motion.

Let's break down the information we have:
Initial speed (u) = 0 (since the aircraft starts from rest)
Final speed (v) = 33 m/s
Distance (s) = 240 m
Acceleration (a) = ?

We can use the equation of motion:
v^2 = u^2 + 2as

Plugging in the values we know:
(33 m/s)^2 = (0)^2 + 2a(240 m)

Rearranging the equation to solve for acceleration (a):
2a(240 m) = (33 m/s)^2
2a(240 m) = 1089 m^2/s^2
480a m = 1089 m^2/s^2

Dividing both sides of the equation by 480 m:
a = 1089 m^2/s^2 / 480 m
a ≈ 2.26875 m/s^2

Therefore, the minimum constant acceleration required for the aircraft to be airborne after a takeoff run of 240 m is approximately 2.27 m/s^2.

v = √(2as)

so, a = v^2/(2s)