The sum of three consecutive even numbers is 48.

_4 + _6 + _ 8 = 48

is it 14 + 16+18

Yes.

To solve this problem, we can use algebraic expressions. Let's assume that the first even number is represented by "x". Since the numbers are consecutive, the second even number would be "x + 2" and the third even number would be "x + 4".

The problem states that the sum of these three consecutive even numbers is 48. We can write this as an equation:

x + (x + 2) + (x + 4) = 48

Now we can simplify the equation:

3x + 6 = 48

Subtracting 6 from both sides:

3x = 42

Finally, divide both sides by 3:

x = 14

So the first even number is 14, the second even number is 14 + 2 = 16, and the third even number is 14 + 4 = 18.

Therefore, the consecutive even numbers that add up to 48 are 14, 16, and 18.