Blake drew square ABCD. Then, he drew the image of it, square A'B'C'D', 2 centimeters to the right of the original figure. Line segment BC is 3 centimeters. How long is B'C'?
A. 1 cm
B. 3 cm
C. 5 cm
D. 6 cm
answers ?
B, I think
3cm
it big d
No they don't
its b
3 cm.
To find the length of B'C', we need to consider the properties of squares.
Since square ABCD was drawn, it means that all four sides are of equal length. Given that line segment BC is 3 centimeters, we know that AB and AD are also 3 centimeters.
Now, when Blake drew the image of square ABCD, square A'B'C'D', 2 centimeters to the right of the original figure, it means that square A'B'C'D' is a translation of square ABCD. Therefore, corresponding sides of both squares will have equal lengths.
Since square ABCD has AB = 3 cm, square A'B'C'D' will also have A'B' = 3 cm.
Now, to find the length of B'C', we need to subtract the common segment AB = A'B' from the total segment B'C'. B'C' is the sum of BC (3 cm) and A'B' (3 cm), which gives us:
B'C' = BC + A'B'
B'C' = 3 cm + 3 cm
B'C' = 6 cm
Therefore, the correct answer is option D. 6 cm.