# Physics

A stone projected vertically upward with a speed of 30ms from the top of a tower of height 50m neglecting the air resistance.determine the maximum height it reach from the ground

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1. recall that the height
h(t) = 50 + 30t - 4.9t^2
And as with all parabolas ax^2+bx+c, the vertex is at x = -b/2a

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2. ho = 50 m = ht. of tower.
h1 = ht above the tower.
h = ht. above gnd.

V^2 = Vo^2 + 2g*h1 = 0,
30^2 + (-19.6)*h1 = 0,
h1 = 45.9 m.

h = ho + h1 = 50 + 45.9 = __ m. above gnd.

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posted by henry2,

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