a capacitor 8uf is charged to a potential difference of 100v. the energy stored by the capacitor is?
C = 8uF = 8*10^-6 Farads.
Energy = C*V^2/2 = (8*10^-6)*100^2/2 = __Joules.
U= 1/2 C*V^2
U= 1/2 (8*10^-6F) (100v)^2
U=0.004J
The energy stored in a capacitor can be calculated using the formula:
E = (1/2) * C * V^2
where E is the energy stored, C is the capacitance, and V is the potential difference.
Given that the capacitance (C) is 8 µF (microfarads) and the potential difference (V) is 100 V, we can substitute these values into the formula to find the energy stored:
E = (1/2) * 8 µF * (100 V)^2
Calculating further:
E = (1/2) * 8 * 10^(-6) F * (100^2) V^2
E = (1/2) * 8 * 10^(-6) F * 10,000 V^2
E = 4 * 10^(-6) F * 10,000 V^2
E = 40 * 10^(-6) F * V^2
E = 40 * 10^(-6) F * 100^2 V^2
E = 40 * 10^(-6) F * 10,000 V^2
E = 400 * 10^(-6) F * V^2
E = 400 microseconds x V^2
Therefore, the energy stored by the capacitor is 400 microseconds times the square of the potential difference, or 400 µJ (microjoules).
To calculate the energy stored in a capacitor, you can use the formula:
E = 0.5 * C * V^2
where:
E is the energy stored in the capacitor
C is the capacitance
V is the potential difference (voltage)
In this case, the capacitance (C) is given as 8µF (microfarads) and the potential difference (V) is given as 100V.
Now, let's calculate the energy stored in the capacitor using the formula:
E = 0.5 * 8µF * (100V)^2
First, let's convert the capacitance from microfarads to farads:
1µF = 1 × 10^-6 F
So, 8µF = 8 × 10^-6 F
Now, substituting the values, we have:
E = 0.5 * (8 × 10^-6 F) * (100V)^2
Simplifying further:
E = 0.5 * 8 × 10^-6 F * 100^2 V^2
E = 0.5 * 8 × 10^-6 F * 10,000 V^2
E = 4 × 10^-6 F * 10,000 V^2
E = 40 × 10^-6 F * 10,000 V^2
E = 400 × 10^-3 F * 10,000 V^2
E = 4 × 10^-1 F * 10,000 V^2
E = 4 × 10^3 V^2
E = 4,000 Joules (J)
Therefore, the energy stored in the capacitor is 4,000 Joules (J).