x-intercept is 3/2 and y-intercept is 1/4 what is the equation?
x-intercept is 3/2 -----> you have the point (3/2, 0)
now it is just like the other question I just did for you
I've got the answer y=-1/6x+1/4, thank you very much for explaining!
It is sometimes useful to use the intercept form for a line. If the intercepts are (a,0) and (0,b) then the line is
x/a + y/b = 1
x/(3/2) + y/(1/4) = 1
2x/3 + 4y = 1
2x + 12y = 3
which is the same as your slope-intercept line.
To find the equation of a line given its x-intercept and y-intercept, you can use the point-slope form or the slope-intercept form.
Let's use the slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
Given that the x-intercept is 3/2 and the y-intercept is 1/4, we have two points: (3/2, 0) and (0, 1/4).
First, let's find the slope (m) using the two points:
m = (y2 - y1) / (x2 - x1)
= (0 - 1/4) / (3/2 - 0)
= -1/4 / (3/2)
= -1/4 * 2/3
= -1/6
Now that we have the slope (m), and the y-intercept (b) is given as 1/4, we can write the equation:
y = mx + b
= (-1/6)x + 1/4
Therefore, the equation of the line is y = (-1/6)x + 1/4.