What is the kinetic energy of a rock of mass 220g after it has fallen freely for 5seconds?g=10m/s2?
V = Vo + g*t = 0 + 10*5 = 50 m/s.
KE = 0.5M*V^2 = 0.5*0.22*50^2 = ___ Joules.
To calculate the kinetic energy of a falling object, you need to use the formula:
Kinetic energy (KE) = (1/2) * mass * velocity^2
In this case, the mass of the rock is given as 220g, which you need to convert to kilograms since the standard unit for mass is kilograms.
To convert grams to kilograms, divide the mass by 1000:
220g รท 1000 = 0.22 kg
The acceleration due to gravity (g) is given as 10 m/s^2.
Since the rock has fallen freely, it will reach a final velocity equal to the product of acceleration (g) and the time of fall (t). Therefore, the final velocity (v) can be calculated as:
v = g * t = 10 m/s^2 * 5 s = 50 m/s
Now that you have the mass (0.22 kg) and the final velocity (50 m/s), substitute the values into the kinetic energy formula:
KE = (1/2) * mass * velocity^2
= (1/2) * 0.22 kg * (50 m/s)^2
Now you can calculate the kinetic energy.