Physics

If ball is rolling from 2 ft down an inclined ramp at an angle of 45deg, what is the speed of the ball when it reaches the ground and how far will it go up a second ramp that is inclined at 30deg?

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asked by George
  1. if it starts 2 feet high is kinetic energy at the bottom will be m g h.
    it will go that same height up the other ramp before it stops.
    Now you did not say if it was a solid ball or whatever
    If I assume it is solid the its moment of inertia is (2/5) m R^2
    and its rotational kinetic energy is (1/2)I omega^2
    since omega = v/R
    the total kinetic energy = (1/2) m v^2 + (1/2) (2/5)m v^2
    = (7/10) m v^2
    so
    m g h = (7/10) m v^2
    v = sqrt (10 g h/7)

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