# math

2log3+log300-log9

1. 👍 0
2. 👎 0
3. 👁 67
1. that would be log(3^2 * 300 / 9) = log(2700/9) = log300
In base 10 logs, that would be 2+log3

or, since 2log3 = log(3^2) = log9, you have
log9 + log300 - log9 = log300

1. 👍 0
2. 👎 0

## Similar Questions

1. ### Math

(I have two questions) 1. Solve for x without a calculator: log3(x^2)=2log3(4)-4log3(5) This is what I have so far: 2log3(x)=log3(4^2)-log3(5^4) 2log3(x)=log3(16/625) ...and now I'm stuck. 2. Simplify: 2log4(9)-2log3

asked by Moe on January 28, 2010
2. ### Logarithm help

using logarithms to solve exponential equations. 5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1 = 9 log(5^x-1) = log9 (log5)(x-1) = log9 x-1 = (log9/log5) x= (log9/log5)-1 x = 2.3652

asked by Joe on September 18, 2015
3. ### Math

Logarithms 3^x-2=18 Work log(3^x-2)=log18 (x-2)log3=log18 xlog3-2log3=log18 x=log3/(log9-log18) e^3x+1=10 lne^3x+1=ln10 3x+1=ln10 I'm stuck here 8^x=5^2x-1 xlog8=(2x-1)log5 xlog8=2xlog5-log5 x=log10/(log5-log8) Are these right?

asked by jackson on September 5, 2016
4. ### math

asked by Hannah on April 25, 2009
5. ### algebra 2 trig

if log3=a then log300 can be expressed as? 1) 100a 2)a+2 3)100+a 4)3a

asked by nikki on January 4, 2014
6. ### Logarithm help

using logarithms to solve exponential equations. 5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1 = 9 log(5^x-1) = log9 (log5)(x-1) = log9 x-1 = (log9/log5) x= (log9/log5)-1 x = 2.3652 Logarithm

asked by Joe on September 19, 2015
7. ### math

Which logarithmic equation is equivalent to the exponential equation below? 9^x=27 A) 27 log9 x B) x log9 27 C) 9 log27 x D) x log27 9

asked by Fran on December 18, 2013
8. ### math

simplify 3^(2log3)

asked by KCS on July 9, 2011
9. ### Trigonometry

log3(x^2)=2log3(4)-4log3(5)

asked by Kali on July 8, 2011
10. ### Basic mathematics

2log3 5+log3 30+3log3 6

asked by Mandar on August 18, 2017