What must be added to x2+10x+23to make it perfect square?
10/2 = 5
(x+5)^2 = x^2 + 10x + 25
so ...
To make the given expression, x^2 + 10x + 23, a perfect square, we need to determine the missing term that should be added.
Step 1: Identify the coefficient of x and divide it by 2.
In this case, the coefficient of x is 10, so we divide it by 2: 10 / 2 = 5.
Step 2: Square the result obtained from step 1.
5 squared is 25.
Step 3: Add the squared result obtained from step 2 to the given expression.
x^2 + 10x + 25
Now the expression, x^2 + 10x + 25, becomes a perfect square because it can be factored into (x + 5)^2.