Maths

A Geometric progression X has a first term of 4a and its sixth term is 256. Another Geometric progression Y has a first term of 3a and its fifth term is 48. Find the:
(i) First term of X
(ii) Sum of the first four terms of X

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  1. for X:
    a = 4a, term(6) = (4a)r^5 = 256
    ar^5 = 64

    for Y:
    a = 3a , term(5) = (3a)R^4 = 48
    aR^4 = 16
    r^5/R^4 = 3
    3R^4 = r^5

    Youd did not state whether R and r are equal , so without that information, that's as far as you can get.

    If R = r, then cleary r = 4
    and (4a)(4^5) = 256
    1024a = 256
    a = 1/4

    I will let you do ii)

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  2. No sum

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  3. how will i do ii

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  4. How did you get a

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  5. I din know how to do it

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  6. What is the full meaning of R

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