the total capacitor of a capacitance 3uf and 6uf are connected in series. calculate the equivalent capacitance
1/C = 1/3 + 1/6
Just like resistors in parallel
Also: C = C1*C2/(C1+C2) = (3*6)/(3+6) =
1/c=1/3+1/6
1/c=6/3
1/c=2
C=2microfarad
The final answer is 9
Why was the capacitor feeling down? Because it couldn't find its equivalent capacitance!
To calculate the equivalent capacitance of capacitors connected in series, you simply add up the reciprocals of the individual capacitances and take the reciprocal of the sum.
So, the equivalent capacitance (Ceq) is given by:
1/Ceq = 1/3µF + 1/6µF
1/Ceq = (2/6µF + 1/6µF)/6µF
1/Ceq = 3/6µF / 6µF
1/Ceq = 3/36µF
Ceq = 36µF/3
Ceq = 12µF
So, the equivalent capacitance of a 3µF and 6µF capacitor connected in series is 12µF.
To calculate the equivalent capacitance of capacitors connected in series, you need to use the formula:
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ...
In this case, you have two capacitors connected in series with capacitances of 3µF and 6µF. Plugging in the values:
1/Ceq = 1/3µF + 1/6µF
To simplify the calculation, you can find the least common multiple (LCM) of the denominators, which is 6µF:
1/Ceq = 2/6µF + 1/6µF
Adding the fractions:
1/Ceq = 3/6µF
Simplifying further:
1/Ceq = 1/2µF
To isolate Ceq, take the reciprocal of both sides:
Ceq = 2µF
Therefore, the equivalent capacitance of the series combination of a 3µF and a 6µF capacitor is 2µF.
1/C=1/C1 + 1/C2
=1/3 + 1/6
=0.5µF