An object is thrown downward at 35.0 m/s from a great height. What is its velocity after 5.0 s?
V = Vo + g*t = 35 + 9.8*5 = 84 m/s.
To determine the velocity of an object thrown downward at 35.0 m/s after 5.0 s, we need to take into consideration the acceleration due to gravity.
The acceleration due to gravity near the surface of the Earth is approximately 9.8 m/s², and since the object is thrown downward, the acceleration due to gravity will be acting in the same direction as its initial velocity.
Given:
Initial velocity (u) = 35.0 m/s (downward)
Time (t) = 5.0 s
Acceleration due to gravity (g) = 9.8 m/s²
To find the final velocity (v), we can use the equation:
v = u + gt
Substituting the given values:
v = 35.0 m/s + (9.8 m/s²)(5.0 s)
Calculating:
v = 35.0 m/s + 49.0 m/s
v = 84.0 m/s (downward)
Therefore, the velocity of the object after 5.0 s is 84.0 m/s downward.
To find the velocity of an object after a certain amount of time, we need to consider the acceleration due to gravity. In this case, since the object is thrown downward, the acceleration due to gravity will be positive.
The acceleration due to gravity near the surface of the Earth is approximately 9.8 m/s^2. We can use this value to find the change in velocity over the given time period.
The initial velocity of the object is -35.0 m/s (negative because it is thrown downward). We can use the equation:
final velocity = initial velocity + (acceleration × time)
Plugging in the values:
final velocity = -35.0 m/s + (9.8 m/s^2 × 5.0 s)
final velocity = -35.0 m/s + 49.0 m/s
final velocity = 14.0 m/s
Therefore, the velocity of the object after 5.0 seconds will be 14.0 m/s downward.