A MAN WALKS 8KM NORTH AND 5KM IN A DIRECTION EAST OF NORTH .FIND THE DISTANCE FROM HIS STARTING POINT
d^2 = 8^2 + 5^5
solve graphically
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vector lab part 1 phys 1030
We need to know how many degrees E. of N.
60degree
To find the distance from the starting point, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the man walks 8km north and 5km east of north, which forms a right-angled triangle. The distance from the starting point is the hypotenuse of this triangle.
Let's label the triangle:
|
|
8km | x km
|_______
5km
Using the Pythagorean theorem, we can write the equation:
hypotenuse^2 = 8km^2 + 5km^2
Simplifying, we have:
hypotenuse^2 = 64km^2 + 25km^2
hypotenuse^2 = 89km^2
To find the hypotenuse, we need to take the square root of both sides:
hypotenuse = sqrt(89km^2)
Calculating the square root of 89, we find:
hypotenuse ≈ 9.43 km
Therefore, the distance from the man's starting point is approximately 9.43 kilometers.