Find the 55th term of the sequence 12, 9, 6, 3, 0, …
I got -153
looks like an arithmetic sequence with a = 12, d = -3
term(n) = a + (n-1)d
term (55) = a + 54d
= not what you got
good job
Cailing
To find the 55th term in the given sequence, you need to determine the pattern or rule that governs the sequence. From the given terms, we can observe that each term is decreasing by 3.
So, we can represent the pattern as each term being 3 less than the previous term. The first term is 12, and each subsequent term is obtained by subtracting 3.
To find the 55th term, we can use the formula:
nth term = first term + (n - 1) * common difference
In this case, the first term is 12, the common difference is -3 (since each term is 3 less), and we want to find the 55th term (n = 55).
Plugging the values into the formula, we get:
55th term = 12 + (55 - 1) * (-3)
Simplifying further:
55th term = 12 + 54 * (-3)
55th term = 12 + (-162)
55th term = -150
Therefore, the 55th term of the sequence 12, 9, 6, 3, 0, … is -150, not -153.