An object reaches a velocity of 147m/s in 15s at a uniform acceleration vertical plane .calculate the size of the uniform acceleration ,also determine whether it was an upward or downward movement from rest.
since you give so + or - sign, we must assume that the 147 m/s is positive.
a = 147/15 m/s^2
Since v is positive, the motion is upward (assuming the usual conventions)
Well, determining whether it was an upward or downward movement from rest is easy! You just need to sit really still and observe if the object falls on your head or if it magically appears from the ground. Just kidding!
To calculate the uniform acceleration, we can use the formula:
v = u + at
Where:
v = final velocity (147 m/s)
u = initial velocity (0 m/s, since it started from rest)
a = acceleration (we need to find this)
t = time (15 seconds)
Now, we can rearrange the formula to solve for acceleration:
a = (v - u) / t
a = (147 m/s - 0 m/s) / 15 s
Therefore, the size of the uniform acceleration is:
a = 9.8 m/s²
Now, since the object started from rest and reached a velocity of 147 m/s, we can conclude that it was an upward movement. But hey, don't be sad! Even if it went downward, there's always gravity to bring it back up again. Gravity loves to play games with objects!
To calculate the uniform acceleration, we can use the equation:
v = u + at
Where:
- v is the final velocity (147 m/s)
- u is the initial velocity (0 m/s, as it starts from rest)
- a is the uniform acceleration we need to find
- t is the time taken (15 s)
Substituting the given values into the equation:
147 = 0 + a * 15
147 = 15a
Dividing both sides of the equation by 15:
a = 147 / 15
a ≈ 9.8 m/s^2
Therefore, the uniform acceleration is approximately 9.8 m/s^2.
To determine whether it was an upward or downward movement from rest, we need additional information about the direction of motion.
To calculate the size of the uniform acceleration, we can use the equation of motion:
v = u + at
Where:
v = final velocity (147 m/s)
u = initial velocity (0 m/s, since the object starts from rest)
t = time taken (15 s)
a = acceleration
Rearranging the equation, we have:
a = (v - u) / t
Substituting the given values, we get:
a = (147 m/s - 0 m/s) / 15 s
a = 147 m/s / 15 s
a ≈ 9.8 m/s²
Therefore, the size of the uniform acceleration is approximately 9.8 m/s².
To determine whether it was an upward or downward movement from rest, we need to consider the direction of the acceleration. Since acceleration due to gravity acts downward, a positive value for acceleration tells us that the object is moving in the upward direction. In this case, the acceleration is positive (9.8 m/s²), so the object is moving upward from rest.