find the first, second and third derivative of : sin3x^2?

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  1. just use the chain rule
    y = sin(3x^2)
    y' = cos(3x^2)(6x)
    y" = -sin(3x^2)(6x)^2 + cos(3x^2)(6)
    y"' = -cos(3x^2)(6x)^3 - sin(3x^2)(2*6x)(6) - sin(3x^2)(6x)(6)
    I'll let you do the algebra. You can always check your results by using
    Just type 3rd derivative sin(3x^2)

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