Three horizontal forces are pulling on a ring at rest. f1 is 6.25 N at 180 degree angle and f2 is 8.90 N at a 243 degree angle direction. What is the y component of F3
To find the y-component of F3, we need to break down the force into its x and y components.
Given that:
- F1 = 6.25 N at a 180 degree angle
- F2 = 8.90 N at a 243 degree angle
Let's calculate the y-component of F1 and F2:
For F1:
The angle is 180 degrees, which means it is along the negative y-axis.
Therefore, the y-component of F1 = F1 * sin(180 degrees)
y-component of F1 = 6.25 N * sin(180 degrees)
y-component of F1 = 6.25 N * 0
y-component of F1 = 0 N
For F2:
The angle is 243 degrees.
To find the y-component, we need to find the angle between the force vector and the y-axis.
The angle between the y-axis and the force vector is 243 - 180 = 63 degrees.
Therefore, the y-component of F2 = F2 * sin(63 degrees)
y-component of F2 = 8.90 N * sin(63 degrees)
Using a scientific calculator:
y-component of F2 = 8.90 N * 0.8910
y-component of F2 ≈ 7.9199 N
Thus, the y-component of F3 is approximately 7.92 N.
To find the y-component of force F3, we need to determine the magnitude and direction of force F3 first. Unfortunately, you did not provide any information about force F3.
Please provide the magnitude and direction (angle) of force F3 so that we can calculate its y-component for you.
add up F1 and F2 using x-y components
Since the three forces balance,
F3y = -(F1+F2)y