Write the arithmetic sequence that has three arithmetic means between -16 and 16.
I got
-16, -8, 0, 8, 16
is it okay?
yes
Thanks Reiny, I have problems with maths
Yes, your arithmetic sequence is correct! The arithmetic sequence you provided is: -16, -8, 0, 8, 16.
To find the arithmetic sequence with three arithmetic means between -16 and 16, you can use the formula for the nth term of an arithmetic sequence:
An = A1 + (n-1)d
where An is the nth term, A1 is the first term, n is the position of the term, and d is the common difference between terms.
In this case, we know that A1 = -16 and An = 16. We also know that there are three arithmetic means, which means there are five terms in total. So n = 5.
To find the common difference, we need to calculate the difference between consecutive terms. In this case, the difference between -16 and -8 is 8, and the difference between -8 and 0 is also 8. Therefore, the common difference is 8.
Plugging the values into the formula, we get:
16 = -16 + (5-1)*8
Simplifying,
16 = -16 + 4*8
16 = -16 + 32
16 = 16
So, the arithmetic sequence is: -16, -8, 0, 8, 16, as you correctly identified. Well done!