Find the measure of each angle in the triangle. I can't post a picture of the triangle it won't let me.
Angle A = 5x +8
Angle B = 4x + 2
Angle C = 8x
Thank you
5x + 8 + 4x + 2 + 8x = 180
17x + 10 = 180
17x = 170
x = 10
(5 * 10) + (4 * 10) + (8 * 10) + 10 = 180
50 + 40 * 80 + 10 = 180
Correction:
Angle A - 50 + 8 = 58
Angle B - 40 * 2 = 42
Angle C - 80
To find the measure of each angle in the triangle, we need to set up an equation using the fact that the sum of the interior angles in any triangle is always 180 degrees.
In this case, we can set up the equation as follows:
Angle A + Angle B + Angle C = 180
Replacing the variables with their respective expressions:
(5x + 8) + (4x + 2) + (8x) = 180
Now, we can combine like terms and solve for x:
17x + 10 = 180
Subtracting 10 from both sides:
17x = 170
Dividing both sides by 17:
x = 10
Now that we have found the value of x, we can substitute it back into the expressions for each angle to find their measures:
Angle A = 5x + 8 = 5(10) + 8 = 58 degrees
Angle B = 4x + 2 = 4(10) + 2 = 42 degrees
Angle C = 8x = 8(10) = 80 degrees
Therefore, the measure of each angle in the triangle is:
Angle A = 58 degrees
Angle B = 42 degrees
Angle C = 80 degrees