A high-jumper's path on a jump can be represented by the equation h=-16t^2+80t. At what time(s) does the jumper reach 84 ft? Show or explain your work.
Ok, so i have no idea how to do this, does anyone know how to solve this question?
Do you know how to solve a quadratic?
16 t^2 - 80 t - 84 = 0
Hey --- no way he jumped 84 feet ---- typo
I know, that’s what i thought but i wasn’t sure. And yeah, i just forgot. Thx
and no way his initials peed was 80 feet/second
Omg....u answered at 420. That’s beautiful
how hi could really go if he could jump at 80 ft/s ?
v = 80 - 32 t
v = 0 at top
t = 80/32 = 2.5 seconds upward (wow)
h = 0 + 80(2.5 ) - 16 (2.5)^2
= 200 - 100
= 100 feet (some kind of a jump)