Graph a circle that has its center at (0,0) and passes through (2,2). Please help ASAP!!! :( I don't know how to do this!!!
Well, don't worry! Graphing a circle is as easy as pie... or should I say, as easy as drawing a smiling face! Here's how you do it:
Step 1: Plot the center of the circle at (0,0).
Step 2: Since the circle passes through (2,2), go ahead and plot that point as well.
Step 3: To determine the radius of the circle, simply measure the distance from the center (0,0) to the point on the circle (2,2), which is conveniently 2 units. So, our radius is 2 units.
Step 4: Now, all you need to do is draw a smooth, round curve that connects all the points on the circle. Make sure it's nice and symmetrical!
And voila! You've got yourself a circle with a center at (0,0) and passing through (2,2). It might not be perfect, but hey, being a bit wonky just adds to its charm!
To graph a circle with center (0,0) and passing through (2,2), follow these steps:
Step 1: Plot the center point.
Start by plotting the center point at (0,0). This is the point where the circle is centered.
Step 2: Determine the radius.
The radius of the circle is the distance from the center to any point on the circle. In this case, the distance between the center (0,0) and the point (2,2) is the radius.
To find the radius:
- Take the difference between the x-coordinates: 2 - 0 = 2
- Take the difference between the y-coordinates: 2 - 0 = 2
- Use the distance formula:
radius = √(x2 - x1)^2 + (y2 - y1)^2
radius = √(2 - 0)^2 + (2 - 0)^2
radius = √(4 + 4) = √8 ≈ 2.83 (rounded to 2 decimal places)
Step 3: Draw the circle.
Using the center point (0,0) and the radius of approximately 2.83, draw a circle on the graph. To do this, plot points around the center such that each point is at a distance of 2.83 units from the center. Connect these points to form the circle.
Note: You can also plot additional points to ensure the accuracy of the circle graph. For example, you can plot points at a distance of 2.83 units from the center along each axis (top, bottom, left, right) to form a square. Then connect these points to create the circle.
Sure, I can help you with that! To graph a circle with its center at (0,0) and passing through (2,2), you can follow these steps:
Step 1: Plot the center point (0,0) on your graph. This point represents the center of the circle.
Step 2: Plot the point (2,2), which is a point on the circumference of the circle. This point will be on the line passing through the center of the circle.
Step 3: Determine the radius of the circle by measuring the distance from the center (0,0) to the point on the circumference (2,2). The radius in this case would be the distance between these two points, which is √( (2 - 0)^2 + (2 - 0)^2 ) = √(4 + 4) = √8 = 2√2.
Step 4: Draw the circle by using the determined radius. Starting from the center point (0,0), draw an arc with a radius of 2√2, passing through the point (2,2). The arc should be symmetrical on both sides of the line connecting the center to the point (2,2).
Step 5: Connect the arc to complete the circle.
Now you have successfully graphed a circle with center (0,0) and passing through (2,2).
The equation of a circle with center ( 0 , 0 ) and radius r is given by :
x² + y² = r²
In this case:
x = 2 , y = 2
x² + y² = r²
2² + 2² = r²
4 + 4 = r²
8 = r²
r = √ 8
r = √ 4 ∙ 2
r = √ 4 ∙ √ 2
r = 2 ∙ √ 2
r = 2 ∙ 1.41
r = 2.82
Draw a circles centered at the origin ( 0 , 0 ) with radius r = 2.82 and mark points x = 2 , y = 2
If you want to see graph go on:
wolframalpha.c o m
When page be open in rectangle paste this:
and click
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go on:
wolframalpha.c o m
When page be open in rectangle paste this:
image a circle center at (0,0) and passes through (2,2)
and click =