a surveyor put stakes at the lettered points. He used string to determine lengths of line segments and a transit to check that the angles at D and B were both right angles.
If CD = 3, CE = 5, DE = 4 and DB = 18, and:
Math sucks stinks is the
if DB are both angles how does DB=18????
How is D the end point of three lines?
I see a line segment BD, adjacent to a 3-4-5 triangle, DCE
Better ask a question and/or 'splain things better.
To find the length of BC, we can use the Pythagorean Theorem, as the surveyor has ensured that the angles at points D and B are right angles.
The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, DB is the hypotenuse, and CD and CB are the other two sides. So, we can set up the equation:
DB^2 = CD^2 + BC^2
Substituting the given values:
18^2 = 3^2 + BC^2
324 = 9 + BC^2
315 = BC^2
To solve for BC, we take the square root of both sides:
√315 = √BC^2
BC ≈ 17.75 (rounded to two decimal places)
So, the length of BC is approximately 17.75 units.