Write the equation of the line which contains the point)0, -3) and whose slope is 4.
A general line equation can be written as
y = mx + c, where m is the slope and c a constant.
so we can write this as y = 4x + c
Substituting the point (0, -3) in the equation, we have
-3 = c
So the equation is
y = 4x - 3
or 4x - y - 3 = 0
The explanation is long but i try to go step by step with it so you can understand it.
first use the formula of line which is :
y=mx+b
you have already your slope which is : 4 which in the formual for line would be your letter m. so substitute that in.
now they give you a set of point. which is (0,-3). NOw you know that 0 is your x point and -3 is your y point.
therefore looking at the equation of the line you substitute these two numbers like so.
y = mx +b
so , you have already the following:
y = 0
x = -3
m = 4
so the equation looks like this now after you substitute.
0=4(-3)+b now you find b so you do the following:
0= -12+b
0+12 = b
12=b
so now you write the equation of the line again:
y=mx+b
so your equation you just substitue the m and b and that would be your answer and it should look like this
y=4x+12
sorry g you are incorrect because they already gave the point and you need to find for b . in your case you put c. so your finding for c.
Yes, Jasmine20, we had to find the constant and I did exactly that. You misread the point (0, -3). The x is 0 and y is -3.
Thank you so much for explaining this
jasmine. It now makes sense.
TAMMY SORRY I DIDN'T REALIZE I DID USE THE Y WRONG AND X JUST REVERSE THEM BUT THE STEPS ARE THE SAME. AND THEN YOU SHOULD GET
Y=4X-3
SORRY FOR THAT LITTLE MISTAKE. i WAS TYPING QUICK AND I DIDN'T CATCH THAT.
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