Math

At 10:00 AM a truck started traveling from point A with a speed of 40mph. 3 hours and 10 minutes later a car started to drive from point A in the same direction with an average speed of 60mph. At what time will the car catch up with the truck?

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asked by Ella
  1. At the catch-up point, they will have travelled the same distance.

    Time taken by car ---- x hrs
    time taken by truck ---- x + 19/6 hrs (which is 3 hrs, 10 min)

    60x = 40(x+19/6)
    60x = 40x + 380/3
    20x = 380/3
    x = 19/3 hrs or 6 hrs, and 20 minutes

    Interpret my answer .

  2. Truck: d1 = 40mi/h * 3.1667h = 126.67 mi. head-start.

    126.67 + 40 * T = 60 * T.
    20T = 126.67,
    T = 6.33h = 6hrs, and 20 min.

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    posted by henry2,

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