What volume of the gas formed,if 0.2 mol of Na will react with water, 2Naoh+H2
2Na + 2H2O ==> 2NaOH + H2
mols Na - 0.2
mols H2 = 1/2 mols H2
1 mol H2 will occupy 22.4 L at STP so 1/2 mol will occupy ....?
mols Na - 0.2
mols H2 = 1/2 mols H2
1 mol H2 will occupy 22.4 L at STP so 1/2 mol will occupy ....?