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Calculus
Given the function f(x)=[h(p(x))]^2 and h(5)=1, h'(5)=2, h'(1)=3, p(1)=5, p'(1)=7, evaluate f'(1)
1 answer
f'(1) = 2h(p(1))*h'(p(1))*p'(1) = 2h(5)*h'(5)*7 = 2*1*2*7 = 28
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