Admission cost to a theatre are adults $5,children $2. If 1000 people paid to enter the theatre and the total receipts were $3800. How many adults attended ?
To find out how many adults attended the theatre, we need to use a bit of algebra.
Let's assume the number of adult attendees is "A" and the number of child attendees is "C." We are given two pieces of information:
1. The admission cost for adults is $5, and the admission cost for children is $2.
2. The total number of people who paid to enter the theatre is 1000, and the total receipts were $3800.
Based on this information, we can set up two equations:
1. A + C = 1000 (equation 1)
- This equation represents the fact that the total number of people who attended the theatre is 1000.
2. 5A + 2C = 3800 (equation 2)
- This equation represents the fact that the total receipts from ticket sales were $3800.
Now, we can solve these equations to find the values for "A" and "C."
To eliminate "C," we can multiply the first equation by 2:
2A + 2C = 2000 (equation 3)
Now, let's subtract equation 3 from equation 2:
5A + 2C - (2A + 2C) = 3800 - 2000
3A = 1800
A = 1800 / 3
A = 600
So, there were 600 adults who attended the theatre.
a+c = 1000
5a+2c = 3800
Now just solve for a.