A number is selected at random from the set y=(18, 19, 20..........28, 29). Find the probability that the number is a prime.
a). 1/4
b). 1/8
c). 1/2
d). 3/4?
the primes contained in your set y are : 19, 23, and 29. So there are 3 of them
how many numbers are contained in y ?
So the probability is .... ?
1÷3
To find the probability that the randomly selected number from the set y=(18, 19, 20..........28, 29) is a prime number, we need to determine the number of prime numbers in the set and divide it by the total number of elements in the set.
First, let's identify the prime numbers in the set y=(18, 19, 20..........28, 29).
The prime numbers in the given set are: 19, 23, and 29.
So, there are 3 prime numbers in the set.
Now, let's determine the total number of elements in the set. We can see that the set starts from 18 and ends at 29, inclusive. Therefore, the total number of elements in the set is (29 - 18) + 1 = 12.
Hence, the probability of selecting a prime number from the set is 3 (number of prime numbers) divided by 12 (total number of elements):
P(prime number) = 3/12 = 1/4.
Therefore, the correct answer is a) 1/4.