If water rises in a capillary tube 5.8cm above the free surface of the outer liquid what will happen to the mercury level in the same tube when it is placed in the ditch of mercury.calculate the difference in level between the mercury surface inside the tube and outside surface tension of water 75×10^-3n/m,that of mercury 547×10^-3n/m,angle of contact of mercury with clean glass 130°,density of mercury 13600kg/m^3, density of water 1000kg/m^3 ?

Question

If water rises in a capillary tube 5.8cm above the free surface of the outer liquid what will happen to the mercury level in the same tube when it is placed in the ditch of mercury.calculate the difference in level between the mercury surface inside the tube and outside surface tension of water 75×10^-3n/m,that of mercury 547×10^-3n/m,angle of contact of mercury with clean glass 130°,density of mercury 13600kg/m^3, density of water 1000kg/m^3 ?

Answer 1

steps or formula for solving it pls

Answer 2

To calculate the difference in level between the mercury surfaces inside and outside the capillary tube, we need to consider the concepts of capillary action and the balance of forces involved.

First, let's calculate the height of rise of water using the given surface tension and contact angle. The formula for capillary rise in a cylindrical tube is:

h = (2 * T * cosθ) / (ρ * g * r)

Where:
h = height of rise
T = surface tension
θ = contact angle
ρ = density of liquid
g = acceleration due to gravity
r = radius of the capillary tube

Given:
T (water) = 75×10^-3 N/m
θ (mercury) = 130°
ρ (water) = 1000 kg/m^3
g = 9.8 m/s^2

Now, we know the height of rise of the water is 5.8 cm, which is equal to 0.058 m:

0.058 = (2 * 75×10^-3 * cos(130°)) / (1000 * 9.8 * r)

Next, let's calculate the radius of the capillary tube:

r = (2 * 75×10^-3 * cos(130°)) / (1000 * 9.8 * 0.058)

Now we can proceed to find the difference in the mercury level. When the capillary tube is placed in the ditch of mercury, the mercury will rise due to capillary action. The same formula as before can be used, but this time we substitute the appropriate values for mercury:

T (mercury) = 547×10^-3 N/m
θ (mercury) = 0° (since mercury wets the glass, the contact angle is zero)
ρ (mercury) = 13600 kg/m^3

Let's calculate the height of rise of mercury:

h = (2 * 547×10^-3 * cos(0°)) / (13600 * 9.8 * r)

Finally, we can find the difference in level between the mercury surface inside and outside the tube:

Difference in level = h - 5.8 cm

Substituting the calculated value of h, we can find the result.

steps or formula for solving it pls

Answer

To calculate the difference in level between the mercury surfaces inside and outside the capillary tube, we need to consider the concepts of capillary action and the balance of forces involved.