A gas occupies a volume of 150cm3 at 25degree celcius and the pressure of 80cm hg.
what will be the volume of the gas if the pressure were reduced to 75cm hg but the temperature remain constant?
75V = 80*150
At constant temperature a gas with a pressure of 750mmhg occupied a volume of 80cm3
To solve this problem, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume at a constant temperature.
Boyle's Law formula is as follows:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure (80 cm Hg)
V1 = initial volume (150 cm^3)
P2 = final pressure (75 cm Hg)
V2 = final volume (unknown)
Given that the temperature remains constant, we can use Boyle's Law to find the final volume.
Using the formula, we can rearrange it to solve for V2:
V2 = (P1 * V1) / P2
Now let's substitute the given values into the formula:
V2 = (80 cm Hg * 150 cm^3) / 75 cm Hg
V2 = 160 cm^3
Therefore, the volume of the gas would be 160 cm^3 if the pressure were reduced to 75 cm Hg while keeping the temperature constant.
To find the volume of the gas when the pressure is reduced, you can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Mathematically, Boyle's Law is expressed as:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
First, let's assign the given values to the variables:
P1 = 80 cm Hg
V1 = 150 cm³
P2 = 75 cm Hg (the reduced pressure)
V2 = volume we need to find
Now, substitute the values into Boyle's Law equation:
80 cm Hg * 150 cm³ = 75 cm Hg * V2
Next, solve for V2:
V2 = (80 cm Hg * 150 cm³) / 75 cm Hg
V2 = 160 cm³
Therefore, the volume of the gas, when the pressure is reduced to 75 cm Hg while keeping the temperature constant, will be 160 cm³.